CE530- OPEN CHANNEL HYDRAULICS
FALL 2019
SECOND MIDTERM
NOVEMBER 13, 2019, 1600-1650
Name: ______________________________ Red ID No. _______________________ Grade: ________
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Instructions: Closed book, closed notes. Use engineering paper.
When you are finished, staple your work in sequence (1 to 4),
and return this sheet with your work.
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(30%) A weir is located at the downstream end of a wide rectangular channel of bottom slope
So = 0.0035 and dimensionless Chezy friction factor f = 0.0035.
The unit-width discharge in the wide rectangular channel is q = 0.5 m3/s/m.
Immediately upstream of the weir, the flow is subcritical, with depth 1.5 m.
- Calculate the Froude number of the normal flow in the upstream channel.
- Calculate the normal flow depth in the upstream channel.
- Calculate the normal flow velocity in the upstream channel.
- Calculate the length of the C1 water-surface profile (See w.s. profile below).
(30%) A hydraulically wide
supercritical flow channel with So = 0.03 flows into a critical flow channel
of So = 0.003. The dimensionless Chezy friction factor f is the same is both channels (f = 0.003).
The unit-width discharge is q = 2.5 m2/s.
Find the length of the C3 water surface profile in the critical flow channel (See w.s. profile below).
[Hint: Calculate the upstream Froude number and the upstream flow depth, then calculate the downstream flow depth;
then calculate the length of the profile by geometry.]
(20%) Please answer the following questions in a brief statement.
- Why is it necessary to design a channel to operate with a minimum Froude number?
- In gradually varied flow in a hydraulically wide channel,
the flow depth gradient Sy is a function of three
parameters. What are these?
- What are the five asymptotic values to which the water surface tend to in
gradually varied flow?
- How many types of water surface profiles are they?
Which ones are horizontal?
(20%) State eight (8) differences between the direct step and standard step methods of steady gradually varied flow computation.
Formulas you may need:
So = f F2
So = Sc F2
F2 = v2/ (gy)
q = vy
yc = (q2/g)1/3
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